Next Round - Codefoces Solution

 "Contestant who earns a score equal to or greater than the k-th place finisher's score will advance to the next round, as long as the contestant earns a positive score..." — an excerpt from contest rules.

A total of n participants took part in the contest (n ≥ k), and you already know their scores. Calculate how many participants will advance to the next round.

Input

The first line of the input contains two integers n and k (1 ≤ k ≤ n ≤ 50) separated by a single space.

The second line contains n space-separated integers a1, a2, ..., an (0 ≤ ai ≤ 100), where ai is the score earned by the participant who got the i-th place. The given sequence is non-increasing (that is, for all i from 1 to n - 1 the following condition is fulfilled: ai ≥ ai + 1).

Output

Output the number of participants who advance to the next round.

Examples 

Input 1

 8 5
 10 9 8 7 7 7 5 5

Output 1

 6

Input 2

 4 2
 0 0 0 0

Output 2

 0

Note

In the first example the participant on the 5th place earned 7 points. As the participant on the 6th place also earned 7 points, there are 6 advancers.

In the second example nobody got a positive score.

Solution

#include <bits/stdc++.h>
using namespace std;
 
#define ll long long
 
int main() {
    ios::sync_with_stdio(0);
	cin.tie(0);
 
    ll n, k, ans=0;
    cin >> n >> k;
    ll arr[n];
    for(ll i=0; i<n; i++) {
        cin >> arr[i];
    }
    for(int i=0; i<n; i++) {
        if(arr[i] >= arr[k-1] && arr[i]!=0) ans++;
    }
    cout << ans;
    return 0;
}